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Select true or false: if 2mg(s) o2(g) → 2mgo(s), δh° = –1203. 6 kj/mol, then formg(s) (1/2)o2(g) → mgo(s), the enthalpy change is δh = –601. 8 kj/mol

Sagot :

According to the given equation ,if 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6

k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, hence the given statement is true.

What do you mean by enthalpy change?

An enthalpy change is roughly equivalent to the energy gained through the production of new chemical bonds in a reaction minus the energy required to break existing chemical bonds.

It describes how a system changes in terms of energy while pressure is constant.

The symbol ΔH stands for enthalpy change. At constant pressure, ΔH is equal to the sum of the system's internal energy and the pressure-volume work it performs on its surroundings.

It  is expressed in units of joules per mole.

If 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6

k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, therefore the above given statement is true.

Learn more about enthalpy change ,here:

https://brainly.com/question/3298339

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