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Sagot :
The value of function f(x) at x = 7 is f(7) = 28
For given question,
we have been given the value of function f(x) at x = 5.
f(5) = 12
We have been given that f'(x) is continuous on 5 and 7
Also, [tex]\int\limits^7_5 {f(x)} \, dx =16[/tex]
We need to find the value of f(7)
Since ∀x, f'(x) = f'(x), f is a primitive function of f' .
And f ' is continuous
[tex]\Rightarrow \int\limits^7_5 {f(x)} \, dx =16\\\\\Rightarrow [f(x)]_5^7=16[/tex]
⇒ [f(7) - f(5)] = 16
⇒ f(7) - 12 = 16
⇒ f(7) = 16 + 12
⇒ f(7) = 28
Therefore, the value of function f(x) at x = 7 is f(7) = 28
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