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What molarity should the stock solution be if you want to dilute 25. 0 ml to 2. 00 l and have the final concentration be 0. 103 m?

Sagot :

tushargupta0691

The stock solution should have a molarity of 8.24M.

Proportional sets. C₁V₁=C₂V₂ is used to calculate an unknown quantity where two solutions/mixtures are proportional.

It follows that the initial concentration times the initial volume will equal the final concentration times the final volume because the sum does not vary.

Using the formula as follows;

                       C₁V₁ = C₂V₂

Where;

C₁ = initial concentration of the stock solution

C₂ = final concentration of the stock solution

V₁ = initial volume of the stock solution

V₂ = final volume of the stock solution

According to the information given in this question,

V₁ = 25mL = 25/1000 = 0.025L

V₂ = 2L

C₁ =?

C₂ = 0.103M

Using the formula; C₁V₁ = C₂V₂

C₁ = C₂V₂/V₁

C₁ = (0.103 × 2) / 0.025

C₁ = 0.206 / 0.025

C₁ = 8.24 M

Therefore, the stock solution should have a molarity of 8.24M.

Learn more about molarity here:

https://brainly.com/question/26873446

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