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Ethylene glycol has a specific heat of 0. 578 cal/(g•°c). if 23. 2 g of ethylene glycol absorbs 75. 6 cal of heat energy, what will the temperature increase be?

Sagot :

Ethylene glycol has a specific heat of 0. 578 cal/(g°c). If 23.2 g of ethylene glycol absorbs 75.6 cal of heat energy. The temperature increase be 5.64°C.

What is Specific Heat ?

The amount of heat needed to raise the temperature of 1 kg of substance.

It is expressed as

Q = mcΔT

where,

Q = Heat energy

m = Mass

c = Specific heat capacity

ΔT = Change in temperature.

Here,

Q = 75.6 cal

m = 23.3 g

c = 578  cal/(g°c)

Now put the values in above formula we get

Q = mcΔT

75.6 cal = 23.2 g ×  578  cal/(g°c) × ΔT

ΔT = 5.64°C

Thus from the above conclusion we can say that Ethylene glycol has a specific heat of 0. 578 cal/(g°c). If 23.2 g of ethylene glycol absorbs 75.6 cal of heat energy. The temperature increase be 5.64°C.

Learn more about the Specific Heat here: https://brainly.com/question/13439286

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