Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

The focal length of a diverging lens is negative. If f = −26 cm or a particular diverging lens, where will the image be formed of an object located 63 cm to the left of the lens on the optical axis?

.... cm to the left of the lens

....What is the magnification of the image?

Sagot :

onyebuchinnaji

The distance of the image formed is 44.27 cm and the magnification of the image is 0.7.

Location of the image

The image distance formed by the lens is calculated as follows;

1/v + 1/u = -1/f

where;

  • v is the image distance
  • u is the object distance
  • f is the focal length of the lens

1/v = -1/f - 1/u

1/v = -(-1/26) - 1/63

1/v = 1/26 - 1/63

1/v = 0.022588

v = 1/0.022588

v = 44.27 cm

What is magnification of lens?

The magnification of a lens is defined as the ratio of the height of an image to the height of an object.

Magnification of the image formed

The magnification of the image is calculated as follows;

Magnification = image distance/object distance

M = 44.27/63

M = 0.7

Thus, the distance of the image formed is 44.27 cm and the magnification of the image is 0.7.

Learn more about magnification here: https://brainly.com/question/1599771

#SPJ1

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.