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The. bond dissociation enthalpies of the H-H bond and the H-Cl bond are 435 kJ mol^-1 and 431 kJ mol^-1, respectively. The ΔHfO of HCL(g) is -92kJ mol^-1 . What is the bond dissociation enthalpy of the Cl-Cl bond?

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The bond dissociation energy of the Cl - Cl bond is -958 kJ mol^-1.

What is the dissociation enthalpy?

Given that;

H-H bond energy =  435 kJ mol^-1

H-Cl bond energy = 431 kJ mol^-1

ΔHfO of HCL(g) = -92kJ mol^-1

Bond dissociation enthalpy of the Cl-Cl bond = x

-92 = 435  +  431 + x

x = -92 - (435  +  431)

x = -958 kJ mol^-1

Learn More about dissociation enthalpy:https://brainly.com/question/9998007?

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