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Using chemical equations, show how the triprotic acid h3po4 ionizes in water. Phases are optional.

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tushargupta0691

The acid that contains three hydrogen ions are called triprotic acid.

The triprotic acid h3po4 ionizes in water:

White solid pure anhydrous phosphoric acid melts into a viscous liquid at 42.35 degrees Celsius. Phosphoric acid, which contains three ion hydrogen atoms, acts as a triprotic acid in an aqueous solution. The hydrogen ions disappear one at a time.

H₃PO₄ (aq)  ⇄  H⁺ (aq) + H₂PO₄⁻ (aq)          Kₐ₁ = 7.5 × 10⁻³

H₂PO₄⁻ (aq)  ⇄  H⁺ (aq) + H₂PO₄²⁻ (aq)       Kₐ₂ = 6.2 × 10⁻³

HPO₄²⁻ (aq)  ⇄  H⁺ (aq) + PO₄³⁻ (aq)            Kₐ₃ = 7.5 × 10⁻³

The first dissociation constant of phosphoric acid indicates that it is not an especially potent acid. It is a weaker acid than hydrochloric acid and sulfuric acid, but stronger than acetic acid. The ease with which each subsequent dissociation stage happens decreases. As a result, H₂PO₄⁻  is a relatively weak acid but HPO₄²⁻ is an extremely weak acid.

Leran more about triprotic acid here:

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