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Annie is considering two different coach journeys from Bristol to Birmingham.

Journey A takes 2 hours and does not stop. The shortest distance by road between the wo coach stations is 143 km, most of which s on the motorway where the speed limit is 31m/s (70 mph).

Journey B costs only half as much, but it takes 3 hours 15 minutes and stops at 5 other towns on the way. This journey is 160 km long, and most of it is on country roads with a speed limit of 22 m/s (50 mph). The speed limit in towns the coach passes through is 13 m/s (30 mph).

Calculate the average speed for each journey in m/s. Think carefully about the units you need to use in your calculations.
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Sagot :

The average speed in the first case is 19.86 m/s and the average speed in the second case is 13.67 m/s.

The formula of average speed is

average speed = total distance / total time

In first case

total distance is 143 km which is also 143000 m

and total time is 2 hours which is also 7200 seconds

so average speed = ( 143000 / 7200 ) m/s

average speed = 19.86 m/s

In second case

total distance is 160 km which is also 160000 m

and total time is 3 hours and 15 minutes which is also 11700 seconds

so average speed = ( 160000 / 11700 ) m/s

average speed = 13.67 m/s

So to conclude with we have find the the average speed in both cases by dividing total distance by total time and in first case we have got our answer as 19.86 m/s and in second case we have got 13.67 m/s.

Learn more about speed here:

https://brainly.com/question/4931057

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