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Sagot :
The Answer to the question is 124.66 grams approximately.
It is given that H₂ will react completely
Molar mass of H₂ = 2 × 1 = 2 gm/mol
Given mass of H₂ = 22 gm
Moles of H₂ reacting = given mass of H₂ / molar mass of H₂
Moles of H₂ reacting = 22 / 2 moles = 11 moles
So, 11 moles of H₂ are taking part in reaction.
The Balanced chemical reaction is as follows as:
N₂ + 3 H₂ → 2 NH₃
It is clear from the reaction that 3 moles of H₂ are making 2 mole of NH₃
3 moles of H₂ → 2 mole of NH₃
1 moles of H₂ → 2/3 mole of NH₃
11 moles of H₂ → (2/3)×11 mole of NH₃
11 moles of H₂ → 22/3 mole of NH₃
So, 11 moles of H₂ will make 22/3 mole of NH₃
22/3 mole NH₃ = mass formed NH₃ / molar mass of NH₃
mass formed NH₃ = 22/3 × molar mass of NH₃
mass formed NH₃ = 22/3 × 17
mass formed NH₃ = 22/3 × 17
mass formed NH₃ = 124.66 grams (approximately)
124.66 grams of NH₃ will be formed.
So, approximately 124.66 grams of NH₃ is formed from 22 grams of H₂.
Learn more about Stoichometry here:
brainly.com/question/25829169
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