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Sagot :
Answer:
[tex]\displaystyle{y-1=5(x+6)}[/tex]
Step-by-step explanation:
A point-slope form is written in the equation of [tex]\displaystyle{y-y_1=m(x-x_1)}[/tex]. Where [tex]\displaystyle{(x_1,y_1)}[/tex] is a coordinate point and [tex]\displaystyle{m}[/tex] is slope.
The definition of parallel is to both lines have same slope. The given line equation has slope of 5. Therefore, we can write the equation in point-slope form as:
[tex]\displaystyle{y-y_1=5(x-x_1)}[/tex]
Next, we are also given the point p(-6,1). Substitute [tex]\displaystyle{x_1}[/tex] = -6 and [tex]\displaystyle{y_1}[/tex] = 1 in:
[tex]\displaystyle{y-1=5[x-(-6)]}\\\\\displaystyle{y-1=5(x+6)}[/tex]
Hence, the line equation that’s parallel to y = 5x - 4 and passes through a point (-6,1) is y - 1 = 5(x + 6)
Answer:
y - 1 = 5 ( x + 6 )
Step-by-step explanation:
- We know that when two lines are parallel the slope of both lines is equal.
- The formula that we use to find an equation of a line is y = m x + c
Here,
m ⇒ slope
- Now let us take a look at the given equation which is already drawn.
y = 5x - 4 ← equation of the old line
Now it is clear to us that,
m ⇒ slope of the line ⇒ 5
c ⇒ y-intercept ⇒ -4
- Therefore, the slope of the new line also will be 5.
That is, m = 5
- The question asked us to write the equation in point-slope form.
- The formula to write the equation in the line in point-slope form is :
y - y₁ = m ( x - x₁ ).
- Here,
m = slope
- Also, we can use the given coordinates to write the equation in point-slope form
( -6 , 1 ) ⇔ ( x₁ , y₁ )
- So, to find the equation of the new line we can replace m, y₁ & x₁ with 5, 1 & -6 respectively.
Let us solve this now
y - y₁ = m ( x - x₁ )
y - 1 = 5 ( x - ( -6) )
y - 1 = 5 ( x + 6 )
- And now let us write the equation of the new line in point - slope form.
y - 1 = 5 ( x + 6 )
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