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Sagot :
The kilograms of BOD5 that are removed in the primary settling tank each day is 447.12 kg.
How to calculate the value?
The BOD5 removed in the primary settling tank each day will be:
= efficiency * influent * average flow rate*24*60*60
The average flow rate is 0.050 m3/s and the BOD5 removal efficiency is 30%,
Influent = 0.345 g/L = 0.000345 kg/L
BOD5 removed in the primary settling tank each day will be:
= 0.3*50*0.000345*24*60*60
= 447.12 kg
Learn more about settling tank on:
https://brainly.com/question/27736862
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