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Grams in 1.083e+24
Molecules Na BR


Please help explain why


Sagot :

Answer:

185 gms o NaBr

Explanation:

Na Br  mole weight = 22.989 +79.904 = 102.893  gm/mole

1.083 x 10^24  molecules / 6.022 x 10^23 molecules / mole = 1.798 moles

102.893  *  1.798 = 185 gms