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Please Hurry !!!!!!!A line has a slope of -4/5. Which ordered pairs could be points on a line that is perpendicular to this line? Select two options.

(–2, 0) and (2, 5)
(–4, 5) and (4, –5)
(–3, 4) and (2, 0)
(1, –1) and (6, –5)
(2, –1) and (10, 9)

Please Hurry A Line Has A Slope Of 45 Which Ordered Pairs Could Be Points On A Line That Is Perpendicular To This Line Select Two Options 2 0 And 2 5 4 5 And 4 class=

Sagot :

Answer:

(–2, 0) and (2, 5)

(2, –1) and (10, 9)

Step-by-step explanation:

1. Find the slope of the what is considered perpendicular to -4/5. To do this, we simply use the reciprocal and multiply it by -1. Therefore, a perpendicular line would have a slope of 5/4.

2. Next, we can plug each of the ordered pairs into [tex]\frac{y2-y1}{x2-x1}[/tex] to see whether or not they have a slope of 5/4. We must do this to all of the ordered pairs until we find 2. Keep in mind that coordinates give you (x, y) in that order, so don't get the x's and y's confused. Additionally, it does not matter which coordinate goes first, just make sure that you get y2 and x2 from the same coordinate, and y1 and x1 from the same coordinate.

  1. [tex]\frac{0-5}{-2-2}=\frac{-5}{-4}=\frac{5}{4}[/tex] The first answer!
  2. [tex]\frac{5-(-5)}{-4-4}=\frac{0}{-8}[/tex] Not an answer
  3. [tex]\frac{4-0}{-3-2}=\frac{4}{-5}[/tex] Not an answer
  4. [tex]\frac{-1-(-5)}{1-6} =\frac{4}{-5}[/tex] Not an answer
  5. [tex]\frac{-1-9}{2-10} =\frac{-10}{-8}= \frac{5}{4}[/tex] The second answer!
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