Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?

Sagot :

elvokipkorir

Answer:

17.25g

Explanation:

From our question, we have been asked to find the mass of water present.

The formula for finding specific heat is given by;

Q = mCp∆T

We have, Q = 0.507 J, ∆T = 0.007° C and we know that Cp of water is 4.2 J/g°C

Rearrange the formula making m the subject.

Which is given by;

m = (Q)/(Cp∆T)

Substituting for the known values

[tex]m \: = \frac{0.507}{4.2 \times 0.007}[/tex]

= 17.24489 g

= 17.25g

Answer:

17.32 gm

Explanation:

Specific heat of water is 4.182 J / g- c

4.182  J /g-c   =  .507/ ( .007 * gm)

solve for gm = 17.32  gm

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.