At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.
What is the hang time equation?
The hang-time of the ball for a player of jump h is given by:
[tex]t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}[/tex]
The expression can be simplified as:
[tex]t = 2\sqrt{\frac{h}{16}}[/tex]
For a player that has a hang time of 0.9s, the jump is found as follows:
[tex]0.9 = 2\sqrt{\frac{h}{16}}[/tex]
[tex]\sqrt{\frac{h}{16}} = \frac{0.9}{2}[/tex]
[tex](\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2[/tex]
[tex]h = 16\left(\frac{0.9}{2}\right)^2[/tex]
h = 3.24 feet.
For a player that has a hang time of 0.8s, the jump is found as follows:
[tex]0.8 = 2\sqrt{\frac{h}{16}}[/tex]
[tex]\sqrt{\frac{h}{16}} = \frac{0.8}{2}[/tex]
[tex](\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2[/tex]
[tex]h = 16\left(\frac{0.8}{2}\right)^2[/tex]
h = 2.56 feet.
The difference is given by:
3.24 - 2.56 = 0.68 feet.
More can be learned about equations at https://brainly.com/question/25537936
#SPJ1
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
