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what are the vertex and axis of symmetry of the equation y=2x^2+16x-12

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konrad509
[tex]y=2x^2+16x-12\\y=2(x^2+8x-6)\\ y=2(x^2+8x+16-22)\\ y=2(x+4)^2-44\\\\ \text{The axis of symetry is }y=-4[/tex]
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