The height of the square-based pyramid is 91.72 in if the length of one side of the base is 23.4 in.
In geometry, it is defined as the shape having a square base with equal sides length and all the vertex of the square's joints at the top, which is perpendicular to the center of the square.
We have a square pyramid.
Length of the pyramid = 23.4 in
The slant height of the pyramid = 93.2 in
From the figure:
Base length CB = DC = 23.4 in
In a right-angled triangle, BCD
Applying Pythagoras theorem:
DC² + CB² = DB²
23.4² + 23.4² = DB²
DB = 33.092 in
OB = (1/2)DB
OB = (1/2)33.092 = 16.546 in
In the right-angle triangle AOB, again applying Pythagoras theorem:
AO² + OB² = AB²
h² + 16.546² = 93.2²
AO = h (height of the square pyramid)
AB = slant height = 93.2 in
After calculating, we get:
h = 91.719 ≈ 91.72 in
Thus, the height of the square-based pyramid is 91.72 in if the length of one side of the base is 23.4 in.
Learn more about the pyramid here:
brainly.com/question/13057463
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