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x^2+ 4x +29=0 solve the quadratic equation by completing the square.

Sagot :

Answer + Step-by-step explanation:

x² + 4x + 29 = 0

⇔ [x² + 4x] + 29 = 0

⇔ [x² + 4x + 4 - 4] + 29 = 0  (just add and subtract 4)

⇔ [x² + 4x + 4] - 4 + 29 = 0

⇔ (x + 2)² - 4 + 29 = 0   (Replace x² + 4x + 4 by (x + 2)²)

⇔ (x + 2)² + 25 = 0

⇔ (x + 2)² = -25  impossible because (x + 2)² > 0 and  -25 < 0

Then there is no solution to the quadratic.