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The zeros of the function () = -(+1)(-3)(+2) are -1.3, and
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and the y-intercept of the function is located at (0,blank

Sagot :

MrRoyal

The zeros of the function f(x) = -(x + 1)(x - 3)(x + 2) are -1, 3, and -2, and the y-intercept of the function is located at (0,6)

The complete question

The zeros of the function f(x) = -(x + 1)(x - 3)(x + 2) are –1, 3, and __and the y-intercept of the function is located at (0,__)

How to determine the zeros?

The function is given as:

f(x) = -(x + 1)(x - 3)(x + 2)

Set the function to 0

-(x + 1)(x - 3)(x + 2) = 0

Divide both sides by - 1

(x + 1)(x - 3)(x + 2) = 0

Split

x + 1 = 0, x - 3 = 0 and x + 2 = 0

Solve for x

x = -1, x = 3 and x = -2

Hence, the zeros of the function f(x) = -(x + 1)(x - 3)(x + 2) are -1, 3, and -2

How to determine the y-intercept?

The function is given as:

f(x) = -(x + 1)(x - 3)(x + 2)

Set x to 0

f(0) = -(0 + 1)(0 - 3)(0 + 2)

Evaluate

f(0) = 6

Hence, the y-intercept of the function is located at (0,6)

Read more about functions at:

https://brainly.com/question/20691826

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