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Sagot :
The dimension of the original photo is 11 inches by 11 inches.
Given that, the area of the reduced photo is 64 square inches.
In the equation [tex](x -3)^{2} = 64[/tex], x represents the side measure of the original photo.
We have to determine the dimensions of the original photo.
What is the equation?
An equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Now, solve the equation for the value of x.
By square rooting on both the side, we get
[tex]\sqrt{(x-3)^{2} } =\sqrt{64}[/tex]
⇒[tex](x-3)=[/tex]±[tex]8[/tex]
⇒[tex]x=8+3=11[/tex] and [tex]x=-8+3=-5[/tex]
The length and width can not be negative.
Therefore, the dimension of the original photo is 11 inches by 11 inches.
To know more about the equation click the link given below:
https://brainly.com/question/2263981
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