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Sagot :
A bicyclist moving at a constant speed takes 10.0 seconds to travel 500 meters down a path inclined 30.0° downward from the horizontal. the vertical velocity of this motion is mathematically given as
V' = 25 m/s. Option C.
What is the vertical velocity of this motion?
Generally, the equation for the Inclined Component is mathematically given as
V=d/s
Therefore
V = 500/10
V= 50 m/s
In conclusion, for the vertical Component
[tex]V'= dsin \theta[/tex]
V'= 50Sin30
V' = 25 m/s
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