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What is the pH of a solution that contains 0.0011 moles of KOH in 393 mL of solution?

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samueladesida43

The pH of a solution that contains 0.0011 moles of KOH in 393 mL of solution is 2.56. Details about pH can be found below.

How to calculate pH?

The pH of a solution can be calculated using the following expression:

pH = - log [H3O+]

However, the hydrogen concentration of the KOH solution can be calculated as follows:

concentration = 0.0011 mol ÷ 0.393 L

concentration = 2.798 × 10-³M

The pH of KOH = - log [2.798 × 10-³M]

pH = 2.56

Therefore, the pH of a solution that contains 0.0011 moles of KOH in 393 mL of solution is 2.56.

Learn more about pH at: https://brainly.com/question/15289741

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