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find the equation of a line that is parallel to y=3x+6 and passes through A
) (0,-2) B. (2,5) C.(4,1)

Sagot :

rspill6

Answer:

Step-by-step explanation:

We'll look for an equation with the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0.

A line parallel to y=3x+6 will have the same slope, 3.

We can write y=3x+b.  Any value of b can be used to generate a parallel line.  

If we want that line to go through a specific point, such as (0,-2), we need to find a value of b that shifts the line so that it includes (0,-2).  This can be done by using that point in the equation y=3x+b:

y=3x+b

-2=3*(0)+b  for point (0,-2)

b = -2

The equation becomes y=3x-2

See the attached plot.

===========================

Do that same thing for the remaining two points.  

For B:  (2,5) The equation is y=3x-1

For C:   (4,1) The equation is y=3x-11

View image rspill6
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