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Answered

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solve this quadratic inequalitie with detailed full explanation
X2≤16
x square less than or equal to 16

Sagot :

konrad509

[tex]x^2\leq16\\x\leq 4 \wedge x\geq -4\\x\in\langle-4,4\rangle[/tex]

different approach:

[tex]x^2\leq16\\x^2-16\leq0\\(x-4)(x+4)\leq0[/tex]

see attachment

[tex]x\in\langle-4,4\rangle[/tex]

View image konrad509
loneguy

[tex]~~~~~~x^2 \leq 16\\\\\implies -\sqrt{16} \leq x\leq \sqrt{16}\\\\\implies -4\leq x \leq 4\\\\\text{Interval notation:}~ [-4,4][/tex]

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