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Given: MN is twice the length of
KM and KM = 8. Find the
perimeter of the total figure.
A. 24
B. 28
C. 38
D. 48


Given MN Is Twice The Length Of KM And KM 8 Find The Perimeter Of The Total Figure A 24 B 28 C 38 D 48 class=

Sagot :

MN=2KM

  • 2(8)
  • 16

MN+KM=24

  • QP/KJ=MN/MK=24/16=3/2

As we can see

QP is almost greater than 3/4th MN

It's atleast 10+ or even 12+

So possible perimeter excluding QJ and KJ is atleast 34 to 36 .

So it can neither be 38 nor 28 .

Only one option yields that's 48(Option D)

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