named347
Answered

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75m X A car moves with a uniform velocity 21 ms-1 from position P and a truck moves from rest with uniform acceleration 2 ms-2 from position Q in the same time in the same direction.

i) Determine the distance travelled in 20 seconds.
ii) How many times the private car will meet? Analyze mathematically.​

75m X A Car Moves With A Uniform Velocity 21 Ms1 From Position P And A Truck Moves From Rest With Uniform Acceleration 2 Ms2 From Position Q In The Same Time In class=

Sagot :

Velocity after 20s for both

  • Car=21m/s
  • Truck=2(20)=40m/s.

Distance traveled for car

  • 20(21)=420m

Distance traveled by truck=

  • s=ut+1/2at²
  • s=1/2(2)(20)²
  • s=400m

#b

Distance from Q

for car

  • 420-75=345m

For truck

  • 400m

The truck will meet the car after 75/21≈4s

Then for 6s the car keeps meeting because after 7 s Truck will archive 22m/s velocity

  • Total meet ups=6+1=7times
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