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How many moles of a gas are contained in 2.085 L at STP?

A. 0.0931 mol
B. 10.8 mol
C. 10.3 mol
D. 1.11 mol

Sagot :

AnjulaReddy
Answer /-

A.0.0931 mol

from ideal gas equation ,

We have ,

PV = nRT

Where P stands where pressure of gas.
We know that pressure of gas at STP = 1 atm

V stands for volume of gas , given Volume is 2.085 L

R stands for gas constant , R = 0.0821

And T stands for absolute temperature and measured in kelvin,T=273K

Now ,

PV = nRT

n = PV/RT

Refer attachment for working
View image AnjulaReddy
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