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What is the Substance that is oxidized in 2K+ S > K2S

Sagot :

belugathecat5

Answer :]

This is an oxidation-reduction (redox) reaction:

S0 + 2 e- → S-II (reduction)

2 K0 - 2 e- → 2 KI (oxidation)

S is an oxidizing agent, K is a reducing agent.

Answer:

K

Explanation:

Here, in this reaction 2 moles of potassium react with 1 mole of sulfur to form 1 mole of potassium sulfide.

Let's compare the electronic configurations of both elements :

⇒ K = {2, 8, 8, 1}

⇒ K can attain noble gas configuration by losing one electron

⇒ K exists as : K⁺

⇒ S = {2, 8, 6}

⇒ S can attain noble gas configuration by the addition of 2 electrons

⇒ S exists as S²⁻

Now, we know that will lose protons when oxidized. Hence, here the substance which is oxidized is K

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