Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

what mass in grams of hydrogen is produced by the reaction of 4.73 g of magnesium with 1.83 of water

Sagot :

Oseni

The mass, in grams, of hydrogen that would be produced from the reaction will be 0.102 grams

Stoichiometric calculations

From the balanced equation of the reaction:

[tex]Mg + 2H_2O -- > Mg(OH)_2 + H_2[/tex]

The mole ration of magnesium to water is 1:2.

Mole of 4.73 grams Mg = 4.73/24.3 = 0.195 moles

Mole of 1.83 grams water = 1.83/18 = 0.102 moles

Hence, water is limiting.

Mole ratio of water to the hydrogen produced = 2:1

Equivalent mole of hydrogen gas produced = 0.102/2 = 0.05 moles

Mass of 0.05 moles hydrogen gas = 0.05 x 2 = 0.102 grams

More on stoichiometric calculations can be found here: https://brainly.com/question/27287858

#SPJ1

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.