Answered

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what is lim x→-3 sqrt x^2-8

Sagot :

If the  -8 is under the square root, then...

[tex]\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\[/tex]

OR

If the -8 is not under the square root, then...

[tex]\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5[/tex]

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

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