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If you dissolve 1.78 g of MgSO4 (Mm = 120.4 g) in 1.10 L of water, what is the molarity of the solution? (Report your answer to four places past the decimal point)​

Sagot :

Eduard22sly

The molarity of the solution given the data from the question is 0.0135 M

What is molarity?

Molarity is simply defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

How to determine the mole of MgSO₄

  • Mass of MgSO₄ = 1.78 g
  • Molar mass of MgSO₄ = 120.4 g/mol
  • Mole of MgSO₄ =?

Mole = mass / molar mass

Mole of MgSO₄ = 1.78 / 120.4

Mole of MgSO₄ = 0.0148 mole

How to determine the molarity

  • Mole of MgSO₄ = 0.0148 mole
  • Volume = 1.1 L
  • Molarity =?

Molarity = mole / Volume

Molarity = 0.0148 / 1.1

Molarity = 0.0135 M

Learn more about molarity:

https://brainly.com/question/15370276

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