Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

9. A computer chip manufacturer knows that 72% of the chips produced are defective.
Suppose 3000 chips are produced every hour, what is the probability that exactly 800
chips are acceptable? Compare the results of using the binomial distributions with
those found using the normal approximation.

Sagot :

MrRoyal

The probability that exactly 800 chips are acceptable is less than 0.000001

How to determine the probability?

The given parameters are:

  • Sample, n = 3000
  • Percentage acceptable, p = 72%
  • Acceptable chips, x = 800

The binomial probability is represented as:

[tex]P(x) = ^nC_x * p^x * (1- p)^{n - x}[/tex]

So, we have:

[tex]P(300) = ^{3000}C_{800} * (72\%)^{800} * (1- 72\%)^{3000 - 800}[/tex]

The data values are large.

So, we use a statistical calculator to evaluate the expression

Using the calculator, we have:

P(300) < 0.000001

Hence, the probability that exactly 800 chips are acceptable is very small i.e. less than 0.000001

Read more about probability at:

https://brainly.com/question/25870256

#SPJ1

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.