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How many grams of aluminum chloride can be produced from 7.32g of ammonium perchlorate?

Sagot :

shimanekgare

Answer:

2.77g of [tex]AlCl_{3}[/tex] can be produced.

Explanation:

Use stoichiometry.

Balanced equation: [tex]3Al + 3NH_{4} ClO_{4}[/tex] ⇒ [tex]Al_{2} O_{3} + AlCl_{3} +3NO + 6H_{2} O[/tex]

[tex]NH_{4} ClO_{4} : AlCl_{3}[/tex]

      3        :     1                        **[tex]n=\frac{m}{M}[/tex]

 0.0623**   :    [tex]x[/tex]                        [tex]n=\frac{7.32}{117.49}[/tex]   = 0.0623

      [tex]3x=0.0623\\x=0.020767[/tex]

[tex]n=\frac{m}{M}[/tex]    

[tex]m=nM[/tex]

m= (0.020767)(133.34)

m= 2.77g                                  

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