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Sagot :
b: boys, g: girls
Without replacement
i) P(b and b) = 60/100 * 59/ 99 = 59/165 = 0.358
ii) P(g and g) = 40/100 * 39/99 = 0.158
iii) we can solve this question using hyper geometric distribution:
(60C1 * 40C1)/ 100C2 = 0.48
Without replacement
i) P(b and b) = 60/100 * 59/ 99 = 59/165 = 0.358
ii) P(g and g) = 40/100 * 39/99 = 0.158
iii) we can solve this question using hyper geometric distribution:
(60C1 * 40C1)/ 100C2 = 0.48
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