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How do I solve. 4x+5y=3 3x-2y=8

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[tex]4x+5y=3 \ \ \ |\times 3 \\ 3x-2y=8 \ \ \ |\times (-4) \\ \\ 12x+15y=9 \\ \underline{-12x+8y=-32} \\ 15y+8y=9-32 \\ 23y=-23 \\ y=\frac{-23}{23} \\ y=-1 \\ \\ 3x-2y=8 \\ 3x-2 \times (-1) = 8 \\ 3x+2=8 \\ 3x=8-2 \\ 3x=6 \\ x=\frac{6}{3} \\ x=2 \\ \\ (x,y)=(2,-1)[/tex]
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