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What is a simplified form of -(14x)^0y^-7z

Sagot :

iGreen
Anything to the power of 0 is one.

Therefore we have:

(1)(y^-7z)

Which simplifies to:

y^-7z

Answer:

[tex]\frac{1}{y^{7z}}[/tex]

Step-by-step explanation:

Given the expression:

[tex]-(14)^0 \cdot y^{-7z}[/tex]

We know that:

[tex]a^0 =1[/tex]

[tex]a^{-1} = \frac{1}{a}[/tex]

then;

[tex]1 \cdot y^{-7z}[/tex]

⇒[tex]y^{-7z}[/tex]

⇒[tex]\frac{1}{y^{7z}}[/tex]

Therefore, the simplified form of [tex]-(14)^0 \cdot y^{-7z}[/tex] is, [tex]\frac{1}{y^{7z}}[/tex].

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