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find the error (-8x^2y^2)^2= -64x^4y^4

Sagot :

Answer:

[tex](-8)^2\neq-64[/tex]

Step-by-step explanation:

Using the distributive property to expand, we have

[tex](-8x^2y^2)^2=(-8)^2(x^2)^2(y^2)^2.[/tex]

Squaring each term, we have

[tex](-8x^2y^2)^2=64x^4y^4.[/tex]

The mistake was that [tex]8^2=64,[/tex] not [tex]-64.[/tex] Using the fact that [tex]8^2=64,[/tex] the right answer would be

[tex]\boxed{64x^4y^4}[/tex].

genan

Answer:

64 shouldnt be negative anymore

Step-by-step explanation:

(-8x^2y^2)^2 = -64x^4y^4

when exapnding the left side it would be...

(-8x^2y^2)^2

Apply exponent rule (-a)^n = a^n

→ (8x^2y^2)^2  

→ (8^2)(x^2)^2

→ (8^2) = 64

→ 64(x^2)^2 = 64x^4

Hope this helps. Let me know if you have any questions !

Have a nice rest of you day :)

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