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A rectangle has a length that is 5 meters less than three times it's width. If the perimeter of the rectangle is 126 meters, what is the area of the rectangle?​

Sagot :

bisoyilaxmipriya2531

step by explaining :

A=wl

P=2(l+w)

Solving forA

A=Pl

2﹣l2=126·5

2﹣52=290m²

answer : 290m²

The area of the rectangle is 782 meter square.

What is an rectangle?

A rectangle is a closed 2-D shape, having 4 sides, 4 corners, and 4 right angles (90°).The opposite sides of a rectangle are equal and parallel.

The area of rectangle is given by length*width and the perimeter of a rectangle is given by 2(length+width).

What will be the area of rectangle?

Let x be the width of the rectangle.

As the length is 5 meter less than three times its width so the length is 3x-5.

The given perimeter is 126 meters so, the equation formed by using the formula of perimeter will be 2(3x-5+x)=126.

on solving the equation we will get x=17.

So, the width of the rectangle is 17 meter.

The length of the rectangle will be 3*17-5=46

The area of rectangle is product of length and width, 17*46=782 meter square.

Therefore, the area of the rectangle is 782 meter square.

Learn more: https://brainly.in/question/7915928

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