justdoingme2ds
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solve for absolute value: 3(r+1)+2>-7

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Answer:

[tex]\huge\boxed{\bf\:r > -4 }[/tex]

Step-by-step explanation:

[tex]3(r+1)+2 > -7[/tex]

Use the distributive property to solve 3 (r + 1).

[tex]3r+3+2 > -7 \\3r + 5 > -7[/tex]

Now, bring 5 to the right hand side of the inequality .

[tex]3r > -7-5 \\3r > -12[/tex]

Divide both sides of the inequality by 3.

[tex]r > \frac{-12}{3} \\\boxed{\bf\:r > -4 }[/tex]

[tex]\rule{150pt}{2pt}[/tex]

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