Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
The game is an illustration of probability, and the probability that each player wins is 1/12
How to determine the probability of winning?
From the question, we have the following parameters:
Number of a pair of numbers = 3
A die has 6 possible outcomes.
So, the probability of getting the first pair is:
P1 = 1/6
The probability of getting the second pair is:
P2 = 1/6
The probability of getting the first and the second pairs is
P = 1/6 * 1/6
Evaluate
P = 1/36
There are three pairs of numbers in total.
So, the probability of winning is:
P(Win) = 3 * 1/36
Evaluate
P(Win) = 1/12
Hence, the probability that each player wins is 1/12
Read more about probability at:
https://brainly.com/question/3142228
#SPJ4
Answer:
1/12.
Step-by-step explanation:
The probability that each player has of winning is 1/12.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.