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a 230v shunt motor delivers 30hp at the shaft at 1120rpm. if the motor has an efficiency of 87% at this load, determine: the total input power the line current

Sagot :

Shunt motors are direct current motors that have parallel windings with identical voltage. The total input power of the shunt motor is 25.724 kW and the line current will be 111.843 A.

What are input power and line current?

Total input power is the ratio of the output power and the efficiency, while the line current is the proportion of input power to an input voltage.

The total input power (total IP) is calculated as:

Given,

Output power (OP) = 30 hp

Efficiency = 0.87

Substituting values:

[tex]\begin{aligned}\text{Total IP} &= \rm \dfrac {OP}{efficiency}\\\\&= \dfrac {30 \times 746 \rm \;watts}{0.87}\\\\&= 25.724 \;\rm kW \end {aligned}[/tex]

Line current is calculated as:

Given,

Input power (IP) = 25.724 kW

Input voltage (IV) = 230 Volt

Solving for line current:

[tex]\begin{aligned} \text{Line current} &= \rm \dfrac{IP}{IV}\\\\&= \dfrac{25.724 \times 10^{3}}{230}\\\\&= 111.843 \;\rm A \end{aligned}[/tex]

Therefore, the total input power of the shunt is 25.724 kW, and the line current is 111.843 A.

Learn more about shunt motor here:

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