Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Help QUICKKKKK please

Help QUICKKKKK Please class=

Sagot :

Answer:

Step-by-step explanation:

Remark

The exposed perimeter of the triangle is just the two smaller legs of the right triangle (6 + 8) + 10 units at the bottom of the rectangle + two 1/2 circles.

The area of the figure is the area of the triangle at the top + the area of the two 1/2 circles + the rectangle in the middle.

Givens

  • Shortest Triangle Leg = 6
  • Middle Triangle Leg = 8
  • Diameter of the 2 half circles
  • pi  = 3.14
  • width of the rectangle in the middle = 8
  • Length of the rectangle = 10
  • d = 8
  • r = d/2 = 8/2 = 4

Formula

A

Perimeter = 2 legs of the triangle + 2 half circles + bottom line

B

Area = (1/2) Leg1*leg2 + pi * r^2 + L * w

Solution

A Perimeter

Perimeter = 6 + 8 + 2*pi *r + 10

Perimeter = 24 + 2*3.14*4

Perimeter = 25.12

B Area

Area = 1/2 * 8 * 6 + 3.14*4^2 + 10* 8

Area = 24 + 50.24+ 80

Area = 150.24

Answer

P = 25.12

Area = 150.24