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Diethyl ether has a δhvap of 29. 1 kj/mol and a vapor pressure of 0. 703 atm at 25. 0°c. What is its vapor pressure at 76. 0°c?

Sagot :

The heat of vaporization is the heat required to turn 1 gm solid into a liquid. The vapor pressure of diethyl ether at 76 degrees celsius is 1.95 atm.

What is vapor pressure?

Vapour pressure is the pressure exerted by the vapors of the equilibrium system. Clausius-Clapeyron equation is used to find the vapor pressure.

[tex]\rm ln \dfrac{P_{2}}{P_{1}} = \rm \dfrac{\delta H}{R} (\dfrac{1}{T_{1}} - \dfrac{1}{T_{2}})[/tex]

Given,

Initial pressure = 0. 703 atm

Initial temperature = 298K

Final temperature = 349 K

Change in enthalpy of vaporization = 29100J/mol

Boltzman constant = 8.314 J/K mol

Substituting values above:

[tex]\begin{aligned} \rm ln \dfrac{P_{2}}{P_{1}} & = \rm \dfrac{\delta H}{R} (\dfrac{1}{T_{1}} - \dfrac{1}{T_{2}})\\\\&= \dfrac{9100}{8.314}(0.0004903)\\\\&= 0.5363\end{aligned}[/tex]

Solving further,

[tex]\begin{aligned} \rm ln \dfrac{P_{2}}{0.703} &= 0.5363\\\\& = \rm e^{0.5363}\\\\&= 1.70\end{aligned}[/tex]

The final pressure is calculated as:

[tex]\rm P_{2} = (0.703 atm)(1.70) = 1.95\;\rm atm[/tex]

Therefore, the vapor pressure at 76 degrees celsius is 1.95 atm.

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