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Sagot :
Alpha particles are accelerated in a cyclotron to a final orbit radius of 0. 50 m. The magnetic field in the cyclotron is 0. 90 t. The period of the circular motion of the alpha particles is closest to 0.11μs.
How do find the time period in a cyclotron?
The period of the circular motion of the alpha particles moving along an in the presence of the magnetic field is given by;
[tex]T = \dfrac{2\pi m}{qB}[/tex]
Alpha particles are accelerated in a cyclotron to a final orbit radius of 0. 50 m. The magnetic field in the cyclotron is 0. 90 t.
We are given;
Mass; m = 6.68 × 10^(-27) kg
Magnetic field;B = 0.90 T
Charge;q = 2e
Now, e is the charge on an electron and it has a value of 1.6 × 10^(-19) C
So, q = 2 × 1.6 × 10^(-19)
q = 3.2 × 10^(-19) C
we know that,
[tex]T = \dfrac{2\pi m}{qB}[/tex]
we have;
[tex]T =\dfrac{ (2\pi \times 6.68 \times 10^{-27})}{(3.2 \times 10^{-19}\times 0.9)}\\T =11.798 \times 10^{-8} s[/tex]
This can also be written as;
T ≈ 0.11 μs
Learn more about cyclotrons;
https://brainly.com/question/17192943
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