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What is the molality of the solute in a 25. 5 percent by mass aqueous solution of formic acid (hcooh)?

Sagot :

Molality is the ratio of the moles of the solute and the mass of the solvent. The molality of the solute is 7.38 m.

What is molality?

Molality is the moles of the solute present in a kilogram of the solvent in a solution of the substance.

Given,

Percent by mass = 25.5 %

In 100 gm of solution = 25.5 gm of  formic acid

Mass of solution = 100 gm

Mass of solute = 25.5 gm

Mass of solvent = 74.5 gm

Moles of solute are calculated as:

[tex]\dfrac{25.5}{46} = 0.55 \;\rm moles[/tex]

Moles of solvent are calculated as:

[tex]\dfrac{74.5}{18} = 4.13\;\rm moles[/tex]

Molality is calculated as:

[tex]\begin{aligned} \rm Molality &= \rm \dfrac{moles}{\text{mass in kg}}\\\\&= \dfrac{0.55}{0.0745}\\\\&= 7.38 \;\rm m\end{aligned}[/tex]

Therefore, 7.38 m is the molality of the solute.

Learn more about molality here:

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