Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A proton of energy 900gev collides with a stationary proton. Find the available energy ea. The rest energy of the proton is 938mev

Sagot :

onyebuchinnaji

The total energy available during the collision of the two protons is determined as 900,938 MeV.

Total energy available during the collision

Based on the principle of conservation of energy, the total energy of the two protons during the collision will be conserved.

Available energy = Er + K

Where;

  • Er is the rest energy
  • K is the kinetic energy

Available energy = 938 MeV + 900 GeV

Available energy = 938 Mev + 900 x 10³ MeV

Available energy = 938 MeV + 900,000 MeV

Available energy = 900,938 MeV

Learn more about rest energy here: https://brainly.com/question/15047418

#SPJ1

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.