Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A circuit has a current of 2 A. If the resistance in the circuit decreases to one-fourth of its original amount while the voltage remains constant, what will be the resulting current? 0. 5 A 2 A 4 A 8 A.

Sagot :

nuhulawal20

If the resistance decreases to (1/4) of its original value while the voltage remained constant, the resulting current is 8A.

Option D) is the correct answer.

What is Ohm's Law?

Ohm’s law states that "the potential difference between two points is directly proportional to the current flowing through the resistance.

It is expressed as;

V = I × R

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given that the circuit has a current of 2A, this means;

V = 2A × R

Next, the resistance in the circuit decreases to one-fourth of its original amount while the voltage remains constant

V = I' × (1/4)R

So we can equate.

2A × R = I' × (1/4)R

2A × R = I' × R/4

2AR = I'R/4

8AR = I'R

I' = 8AR / R

I' = 8A

If the resistance decreases to (1/4) of its original value while the voltage remained constant, the resulting current is 8A.

Option D) is the correct answer.

Learn more about potential difference here: brainly.com/question/2364325

#SPJ1

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.