Answered

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sound sensor display reads 40 dB inside and outside it reads 80dB. how many times louder is it outside than inside?

Sagot :

The difference is (80 dB - 40 dB) = 40 dB.

The sound is 40 dB louder outside.

Each 10 dB means 10 times more sound power.

40 dB louder means 10x10x10x10 times more sound power.

That's 10,000 times more sound power outside than inside.

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