christenthompson
Answered

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find the distance between (5,5) and (8,1)

Sagot :

TheHelperOfHeck

Answer:

5

Step-by-step explanation:

Imagine a triangle with two of the corner points being the points (5,5) and (8,1)

The length and width would be 3 and 4 to find the hypotenuse (distance) do

3^2+4^2=x^2

9+16=x^2

25=x^2

x=5

WiFiAssistant

[tex]here \: is \: your \: answer...[/tex]

Step-by-step explanation:

Let (x1,y1) = (5,5) and (x2,y2) = (8,1)

By using distance formula,

[tex]d \: = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]

[tex]d = \sqrt{ {(8 - 5)}^{2} + {(1 - 5)}^{2} } [/tex]

[tex]d = \sqrt{ {(3)}^{2} + {( - 4)}^{2} } [/tex]

[tex]d = \sqrt{9 + 16} [/tex]

[tex]d = \sqrt{25} [/tex]

[tex]d = 5 \: units[/tex]

Therefore, the distance between (5,5) and (8,1) is 5 units

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