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IF 0.5 MOL NITROGEN GAS HAS A VOLUME OF II.0 L SOME TEMPERATURE AND
PRESSURE, WHAT WOULD THE VOLUME BE OF 0.8 MOL OF NITROGEN GAS AT THE SAME
TEMPERATURE AND PRESSURE VALUES?
Vi= 0.5 mol


Sagot :

Answer:

17.92L or 17.92dm³1

Explanation:

number of moles of a gas = volume of that gas/ 22.4(S.V.P)

0.8 mol = x / 22.4

cross multiplication

x = 22.4 × 0.8

x = 17.92

:. the volume of 0.8 mol of nitrogen gas is 17.92dm³ or 17.92L